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the vertices of a abc are a4 6 b1 5 and c7 2 a line is drawn to intersect sides ab and ac at d and e respectively such that adab aeac 14 calculate
y2 t2 - 3 is the actual implicit solution to y ty y2 -1 at such point i will ask that you trust me that it is actually a solution to the
its easier to describe an explicit solution in this case and then tell you what an implicit solution is not and after that provide you an
the actual solution is the specific solution to a differential equation which not only satisfies the differential equation although also satisfies
the general solution to a differential equation is the most common form which the solution can take and does not take any initial conditions in
the interval of validity for an ivp along with initial conditionsyt0 y0 orand ykt0 ykthere is the largest possible interval on that the solution is
suppose a and b be two non-empty sets then every subset of a chi b describes a relation from a to b and each relation from a to b is subset of
an ivp or initial value problem is a differential equation with an appropriate number of initial conditionsillustration 3 the subsequent is an ivp4x2
find the relation between x and y when the point xy lies on the straight line joining the points 2-3 and 14 hint use area of triangle is 0ans
initial conditions are a set of conditions or a condition on the solution which will permit us to find out that solution which we are after
the midpoint of the line joining 2a 4 and -2 3b is 1 2a 1find the values of a amp b ans a 2 b 2ans a2a
find the coordinates of the point p which is three -fourth of the way from a 3 1 to b -2
the two opposite vertices of a square are -1 2 and 3 2 find the coordinates of the other two
find the centre of a circle passing through the points 6 -6 3 -7 and 33also find the
the cartesian product also called as the cross product of two sets a and b shown by achib in the similar order is the set of all ordered pairs x y
if two vertices of an equilateral triangle are 0 0 and 3 0 find the third vertex ans 32 3radic 32 or 32 -3radic 32ans oa ob aboa2
a solution to a differential equation at an interval alpha lt t lt b is any function y t that satisfies the differential equation in question on the
a linear differential equation is of differential equation which can be written in the subsequent formant yn t a n-1 t yn-1 t a1t yt a0 t yt g
a differential equation is termed as an ordinary differential equation abbreviated through odes if this has ordinary derivatives in it similarly a
the order of a differential equation is the huge derivative there in the differential equation under the differential equations as listed above in
the first definition which we must cover is that of differential equation a differential equation is any equation that comprises derivatives either
there isnt actually a whole lot to this section this is mainly here thus we can get several basic concepts and definitions out of the way most of
if the points 5 4 and x y are equidistant from the point 4 5 prove that x2 y2 - 8x - 10y 39 0ans ap pb ap2 pb25 - 42 4 - 52 x - 42 y -
if a b and p are the points -4 3 0 -2 and alphabeta respectively and p is equidistant from a and b show that 8alpha - 10beta 21 0ans ap pb
a non-empty set or group of which all the sets under concern are subsets is known as the universal set in any part of application of set theory all