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a bucket of height 8 cm and made up of copper sheet is in the form of frustum of right circular cone with radii of its lower and upper ends as 3 cm
a solid is in the form of a right circular cone mounted on a hemisphere the radius of the hemisphere is 35 cm and the height of the cone is 4 cm the
provided a homogeneous system of equations 2 we will have one of the two probabilities for the number of solutions1 accurately one solution
specified a system of equations 1 we will have one of the three probabilities for the number of solutions1 no solution2 accurately
review systems of equations - the traditional initial point for a linear algebra class we will utilize linear algebra techniques to solve a system of
for this point weve only looked as solving particular differential equations though many real life situations are governed through a system of
find the laplace transforms of the specified functionsa ft 6e5t et3 - 9b gt 4cos4t - 9sin4t 2cos10tc ht 3sinh2t
as we saw in the previous section computing laplace transforms directly can be quite complex generally we just utilize a table of transforms when
if the minute hand of a big clock is 105 m long find the rate at which its tip is moving in cm per
a circular disc of 6 cm radius is divided into three sectors with central angles 1200 1500900 what part of the circle is the sector with central
the area enclosed between two concentric circles is 770cm2 if the radius of the outer circle is 21cm find the radius of the inner circleans
the definition- the definition of the laplace transforms we will also calculate a couple laplace transforms by using the definitionlaplace
in this section we will be searching how to utilize laplace transforms to solve differential equations there are various types of transforms out
it is the full blown case where we consider every final possible force which can act on the system the differential equation in this casemu gammau
we will firstly notice the undamped case the differential equation under this case ismu ku ftit is just a non-homogeneous differential equation
it is the simplest case which we can consider unforced or free vibrations sense that ft 0 and undamped vibrations implies that g 0 under this case
it is the catch all force if there are some other forces which we decide we need to act on our object we lump them in now and call this good we
the subsequent force that we want to consider is damping this force may or may not be there for any specified problemdampers work to counteract any
spring fswe are going to suppose that hookes law will govern the force as the spring exerts on the object this force will all the time be present
there is a list of the forces which will act on the objectgravity fgthe force because of gravity will always act on the object of course such force
find the circumference of a circle whose area is 16 times the area of the circle with diameter 7cm ans
the sum of the diameters of two circles is 28 m and their difference of circumferences is 088m find the radii of the two circles ans 77
determine a particular solution for the subsequent differential equationyprimeprime - 4 yprime -12 y 3e5t sin2t te4tsolutionthis example is the
here lets take a look at sums of the fundamental components andor products of the fundamental components to do this well require the following
example find out a particular solution toy - 4y - 12 y 3e5tsolutionthe point here is to get a particular solution though the first thing that were