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any point on parabola k2kperpendicular distance formuladk-k2-1212differentiating and putting 01-2k0k12therefore the point is 14
let u sinx then du cosx dx so you can now antidifferentiate eu du this is eu c esinx c then substitute your range 0 to piesin
if roots of x-px-q c are a and bwhat will be the roots of x-ax-b -c please explainans x-px-qcx2-pqx-c0hence
the hcf amp lcm of two expressions are respectively x3 and x cube-7x6if one is x square2x-3 other issolutionx3 x3-7x6 x22x-3
yx44lnx-x416 then dydx solution dydx-x342lnx-12 means
a train goin from delhi to jaipur stops at 7 intermediate stations 5 persons enter the train during the journey with 5 difefrent tickets of same
the angles between three non-zero and non coplanar vectors ab and c are alpha between b and cand beta between c and aand gamma between a and bthe
two persons a and b agree to meet at a place btween 11 to 12 noon the first one toarrive waits for 20 min and then leave if the time of thir
ythetasininthetacosinthetathen find dydividedthetasolution ythetasininthetacosinthetaapplying uv rulethen dydividedtheta sininthetacosintheta
if i worked 7 13 hours and planted 11 trees how many hours did it take to plant each
two indiana state senate candidates must decide which city to visit the day before the november election the same four cities are available for both
draw a tangent on the lens where you want to find normal then line perpendicular to tangent gives normal at that
if roots of x-px-q c are a and bwhat will be the roots of x-ax-b -c please explainsolution x-px-qcx2-pqx-c0hence
lhscos 12cos 60cos 84cos 12cos 84cos 60cos 122cos 72 cos 1212sin 18cos 1212radic5 -14cos 121radic5 -12cos 12radic5 12cos 12 rhscos 48cos 242cos
is it possible to add two vectors of unequal magnitude and get a resultant of zeroplease explain alsoans no it is not possible as if the magnitude
normal 0 false false false en-in x-none x-none microsoftinternetexplorer4
from 0-gt1int sqrt1-x2 solutioniintsqrt1-x2dx sqrt1-x2intdx - int-2x2sqrt1-x2intdx ----gtintegration by parts
sin cot-1 cos tan -1xtan-1 x a gt tan a xsec a radic1x2 gt cos a 1radic1x2 so a cos-11radic1x2sin cot-1 cos tan -1x
no the parallel lines do not meet at infinity because the parallel lines never intersect each other even at infinityif the intersect then it is
a man is known to speak truth 3 out of 4 timeshe throws adie and reports it is a six find the probability that it is actually a sixsolution
limit 0 to 23x22 solution integrate 3x2 to x3 and 2 to 2x and apply the limit from 0 to 2answer is 12
in and ap 123456789111213141516171819 and like that nonzzero digit find tnsolution first break the n number in terms of 10s power for eg if n3259
yfax and fsinxlnx find dydx solution dydx axlnxfax 1but fsinx lnx implies fx lnarcsinxhence fx 1arcsinx 1 1-x2 2 implies fax
sin2xxsin2xcosxcos2xsinx 2sinxcosxcosx-2sin2xsinx