Start Discovering Solved Questions and Your Course Assignments
TextBooks Included
Active Tutors
Asked Questions
Answered Questions
example determine the equation of the line which passes through the point 8 2 and is parallel to the line given by 10 y 3x -2solutionin both of
determine if the line that passes through the points -2 -10 and 6 -1 is parallel perpendicular or neither to the line specified by 7 y - 9 x 15
slope-intercept formthe ultimate special form of the equation of the line is possibly the one that most people are familiar with it is the
example write down the equation of the line which passes through the two points -2 4 and 3 -5solutionat first glance it might not appear which well
the next special form of the line which we have to look at is the point-slope form of the line this form is extremely useful for writing the equation
first larger the number ignoring any minus signs the steeper the line thus we can use the slope to tell us something regarding just how steep a
standard form of the linelets begin this section off along a quick mathematical definition of a line any equation that can be written in the
x-intercept if an intercept crosses the x-axis we will call it as x-intercept y-interceptsimilar if an intercept crosses the y-axis we will
the last topic that we want to discuss in this section is that of intercepts notice that the graph in the above instance crosses the x-axis in
problem 1work through talpac 10 basics refer to attached handout answer the set of questions at the end of tutorial moduleproblem 2referring to both
1 four different written driving tests are administered by a city one of these tests is selected at random for each applicant for a drivers license
application of linear equationswe are going to talk about applications to linear equations or put in other terms now we will start looking at
solve out each of the following equations 3 x 5 2 -6 - x - 2xsolutionin the given problems
1 if the equation has any fractions employ the least common denominator to apparent the fractions we will do this through multiplying both sides of
to solve out linear equations we will make heavy use of the following facts1 if a b then a c b c for any c all it is saying that we can add
linear equationswell begin the solving portion of this chapter by solving linear equationsstandard form of a linear equationa linear equation is any
there is one final topic that we need to address as far as solution sets go before leaving this section consider the following equation and
for inequalities we contain a similar notation based on the complexity of the inequality the solution set might be a single number or it might be
the complete set of all solutions is called as the solution set for the equation or inequality there is also some formal notation for solution
first a solution to an equation or inequality is any number that while plugged into the equationinequality will satisfy the equationinequality thus
multiply the given below and write the answer in standard form2 - radic-100 1 radic-36 solutionif we have to multiply this out in its present form
division of complex numbernow we gave this formula a long with the comment that it will be convenient while it came to dividing complex numbers so
multiply following and write the answers in standard form a 7i -5 2i b 1 - 5i -9 2i solutiona thus all that we have to do is distribute
multiplication of complex numbersafter that lets take a look at multiplication again along with one small difference its possibly easiest to just
performs the mentioned operation and write the answers in standard form -4 7i 5 -10i solutionactually there isnt much to do here other than add or