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Q : Microprocessors like the 68000 use address and data buses....

Computer Engineering :

question microprocessors like the 68000 use address and data buses and special-purpose dedicated control pins to

Q : The 68000 uses a rw output to indicate a read or a write....

Computer Engineering :

question 1 the 68000 uses a rw output to indicate a read or a write cycle an alternative is to employ separate re read

Q : Why does the 68000 require only one address strobe as but....

Computer Engineering :

question 1 why does the 68000 require only one address strobe as but two data strobes uds and lds would a single pair

Q : The 68000 bus cycle lasts 4 nt y seconds where n i s the....

Computer Engineering :

question 1 what is the meaning of data setup time and data hold time can either of these values be zero can they be

Q : Describe the 68000 read cycle explaining the actions that....

Computer Engineering :

question 1 describe the 68000 read cycle explaining the actions that take place and the relationship between them2 what

Q : Design a universal programmable interface that can connect....

Computer Engineering :

question 1 design a universal programmable interface that can connect almost any peripheral to a 68000 system-even if

Q : What is the difference between the way in which the 68000....

Computer Engineering :

question 1 what is the difference between the way in which the 68000 and the 68020 use the function code outputs2 what

Q : If you had to design a 32-bit address and data interface to....

Computer Engineering :

question - if you had to design a 32-bit address and data interface to a modern microprocessor how would you go about

Q : Identify these four parameters and explain how they cause....

Computer Engineering :

question identify these four parameters and explain how they cause timing problems delays in interface logic eg address

Q : Assume that we are using a 68000-based system what 68000....

Computer Engineering :

question 1 give the size ie number of addressable locations of each of the following memory blocks as a power of 2a 2

Q : A 68000 memory map is divided into equal-sized pages for....

Computer Engineering :

question 1 a 68000 memory map is divided into equal-sized pages for each of the block sizes of q1 in each case indicate

Q : The 68000 has an a00 address bit in all its address....

Computer Engineering :

question the 68000 has an a00 address bit in all its address registers including the pc the 68000 has no a00 pin why2

Q : A memory board has 2 mbytes of ram composed of 256k x 8 ram....

Computer Engineering :

question design an address decoder for the following 68000 systema 256 kbytes of rom using 128k x 8-bit chipsb 4 mbytes

Q : When the 68000 executes a write operation to an odd byte it....

Computer Engineering :

question 1 when the 68000 executes a write operation to an odd byte it asserts lds and places data on d00 - d07 what

Q : A 68000 subroutine is designed to search a table for a....

Computer Engineering :

question a 68000 subroutine is designed to search a table for a longword on entry ao contains the starting address of

Q : Draw a diagram to illustrate each of the following triplets....

Computer Engineering :

question draw a diagram to illustrate each of the following triplets the first element in each triplet is a lower bound

Q : Write a subroutine to carry out the operation xy z where x....

Computer Engineering :

question 1 why is it a good idea to pass parameters to and from a subroutine by means of the stack2 write a subroutine

Q : Write a subroutine called addabc that performs the....

Computer Engineering :

question write a subroutine called addabc that performs the operation c a b the three variables a b and c are all

Q : Why is c so popular as a systems programming language in....

Computer Engineering :

question 1 why is c so popular as a systems programming language in applications such as embedded microprocessor

Q : Explain what the following fragment of c code....

Computer Engineering :

question explain what the following fragment of c code

Q : The following two fragments of code are a c program and the....

Computer Engineering :

question the following two fragments of code are a c program and the 68000 assembly language output produced by

Q : Write a subroutine in 68000 assembly language to calculate....

Computer Engineering :

question write a subroutine in 68000 assembly language to calculate the value of x x2 x4 the parameter x is a 16-bit

Q : The 68000 has three interrupt request inputs ipl0--ipl2....

Computer Engineering :

question 1 in 68000 terms what is the difference between a clock cycle a bus cycle and an instruction cycle2 the 68000

Q : The quoted physical address space of the 68000 is 16 mbytes....

Computer Engineering :

question 1 the quoted physical address space of the 68000 is 16 mbytes ie 2 24 bytes i could maintain that it is 64

Q : Why cannot the 68000 be single-stepped through instructions....

Computer Engineering :

question 1 why cannot the 68000 be single-stepped through instructions simply by halting its clock after as has been