You put a diode in a microelectronic circuit to protect the system in case an untrained person installs the battery backward. In the correct forward-bias situation, the current is 225 mA with a potential difference of 111 mV across the diode at room temperature (300 K). If the battery were reversed, so that the potential difference across the diode is still 111 mV but with the opposite sign, what would be the magnitude of the current in the diode?