Write an expression that will cause the following code to

Question

Programming in C:

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".

#include
#include

int main(void) {
double targetValue = 0.3333;
double sensorReading = 0.0;

sensorReading = 1.0/3.0;

if (/* Your solution goes here */) {
printf("Equal\n");
}
else {
printf("Not equal\n");
}

return 0;
}