Write a function named digitcount that takes one parameter


You need help writing two different functions in python. Python only please!

The first function -

Write a function named digit_count that takes one parameter that is a number (int or float) and returns a count of even digits, a count of odd digits, and a count of zeros that are to the left of the decimal point.

Return the three counts in that order: even_count, odd_count, zero_count.

Be careful of the "edge case" where the number starts with a decimal point-conversion of such a number to a string places a zero before the decimal point.

See correct behavior in the final test case below.

For example:

digit_count(1234567890123)

returns (5, 7, 1)

digit_count(123400.345)

returns (2, 2, 2)

print(digit_count(123.))

returns (1, 2, 0)

print(digit_count(.123))

returns (0, 0, 0)

The second function -

Write a function named float_check that takes one parameter that is a string and returns True if the string represents a float and False otherwise. For this function we define a float to be a string of digits that has at most one decimal point. Note that under this definition an integer argument will return True. Remember "edge cases" such as "45." or ".45"; both should return True.

For example:

float_check('1234')

returns True

float_check('123.45')

returns True

float_check('123.45.67')

returns False

float_check('34e46')

returns False

float_check('.45')

returns True

float_check('45.')

returns True

float_check('45..')

returns False

Need help writing those two functions as described in python.

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Python Programming: Write a function named digitcount that takes one parameter
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