The first-order decomposition of N2O5 at 328 K has a rate constant of 1.70 . 10-3 s-1. If the initial concentration of N2O5 is 2.88 M, what is the concentration of N2O5 after 12.5 minutes?
I already know the answer is .805M, but I'm not sure why my professor solved it the way he did:
ln [A] = -kt + ln [Ao]
ln [A] = (-1.70 x 10^-3 x 12.5 x 60) + ln (2.88)
Why is the temperature 60 instead of 328K?