The input to the oscilloscope can be modeled as a 1 [M Ohm] resistor in parallel with a capacitor in the range of about 20[pF]. When the scope probe is properly calibrated, it can be modeled as a 9[M Ohm] resistor in parallel with a capacitor having a capacitance l/9th that of the oscilloscope input capacitance. When you calibrate the probe, you are in fact adjusting the probe capacitance so that it has the correct value. If the scope probe is not properly calibrated, is an error introduced into your measurement? What is the nature of the error? Is there also an error in dc measurements made using the scope probe? Repeat the calculation of the output voltage of the circuit in Figure 1 assuming that the oscilloscope is connected to the circuit output. Repeat this calculation again assuming that the oscilloscope and the scope probe are connected to the circuit output. In which case is the circuit loading more of a problem? Why? Assume that the scope probe is connected to the oscilloscope. Calculate the impedance of the scope probe and oscilloscope combination at the terminals of the scope probe. Do this calculation for a signal frequency of 3 [kHz] and 10[kHz]. If the probe and oscilloscope were connected to a circuit output, for which frequency would the circuit loading be more of a problem? Why? Devise an experiment for determining the capacitance of an unmarked capacitor. Do not use time constant methods.