When benzene (C6H6 ) reacts with bromine (Br2 ), bromobenzene (C6H5Br ) is obtained: C6H6+Br2→C6H5Br+HBr
What is the theoretical yield of bromobenzene in this reaction when 28.0 g of benzene reacts with 60.7 g of bromine?
If the actual yield of bromobenzene was 54.0 g, what was the percentage yield?