What would the probable percent error inn1n2 then be and


Compute the all part of given question.

Question- If a measurement M is made with a probable error of ±m, then the probable percent error is ± m/M x 100% and may be designated as ±m'%. Similarly, if another measurement of Nis made with a probable error of ±n, then its probable percent error will be ±n/N x 100% or ±n'%. If result involves the multiplication of M times N, then the probable percent error in the product of M times N, MN, will be±?(m'2+n'2)%. Similarly, if result involves the division of M by N, then the probable percent error in the quotient of M and N, M/N, will also be±?(m'2+n'2)%. If the number of turns in the experiment n1 was equal to 5.00±.01.

Part 1- What would the probable percent error inn1/n2 then be?

Part 2- What would the probable percent error be if the number of turns were 1.00±.01?

Part 3- What fact does this problem emphasize?

You need experts help to evaluate the above question.

Request for Solution File

Ask an Expert for Answer!!
Physics: What would the probable percent error inn1n2 then be and
Reference No:- TGS0965352

Expected delivery within 24 Hours