One cell is set up with copper and lead electrodes in contact with CuSo4(aq) and Pb(NO3)2 (aq), respectively. If the Pb2+ and Cu2+ concentrations are each 1.0 M, what is the overall cell potential? If sulfuric acid is then added to the Pb(NO3)2 (aq) solution, thereby forming a precipitate of PbSo4, what will happen to the cell potential?