What volume (in ml) of 0.0032 m na2cr2o7 would be required
What volume (in mL) of 0.0032 M Na2Cr2O7 would be required to titrate a 20 mL aliquot of water with COD of 720 ppm? The formula is volume (Na2Cr2O7) = Moles(Na2Cr2O7)/[(Na2Cr2O7]. how to obtain the moles of Na2Cr2O7
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