Suppose you can dissolve an aluminum soft drink can in an (aq) base such as potassium hydroxide.
2 Al(s) + 2KOH (aq) + 6H2 0 ---> 2KAl (OH)4(AQ) + 3H2(g)
If you place 2.05 g of aluminum in a beaker with 185 mL of1.35 M KOH, will any aluminum remain (show all calculations). What mass of KAl (OH)4 is formed?