What is the radius of the path taken by the particle


At t1=2.00s, the acceleration of a particle in counterclockwise circular motion is (6m/s^2)i+(4m/s^2)j. It moves at constant speed. At time t2=5s, its acceleration is (4m/s^2)i + (-6m/s^2)j. what is the radius of the path taken by the particle?

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Physics: What is the radius of the path taken by the particle
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