What is the ph of the resulting
500.0 mL of 0.120 M NaOH is added to 595 mL of 0.250 M weak acid (Ka = 2.95 × 10-5). What is the pH of the resulting buffer?
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5000 ml of 0120 m naoh is added to 595 ml of 0250 m weak acid ka 295 times 10-5 what is the ph of the resulting
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