What is the mole fraction of c2h2nbsppresentnbsp note the

Question

At 2000 K, K_c = 0.154 for the reaction below.

2 CH₄(g) → C₂H₂(g) + 3 H₂(g)

If a 1.75-L equilibrium mixture at 2000 K contains 0.95 mol each of CH₄(g) and H₂(g), answer the following questions.

(a) What is the mole fraction of C₂H₂ present?  (Note: The mole fraction of C₂H₂ is equal to the number of moles of C₂H₂divided by the total number of moles.)

Enter your answer with 2 significant digits.

Enter scientific notation as 1.23E4.

Enter only numbers in your answer. (Do not include units.)

The mole fraction of C₂H₂ is   --------

(b) If the equilibrium mixture at 2000 K is transferred from a 1.75-L flask to 10.0-L flask, will the number of moles of C₂H₂(g) increase, decrease, or remain unchanged?