Aluminum metal dissolved in hydrochloric acid as follows:
2Al(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2(g)
a. What is the minimum volume of 6.0 M HCl(aq) needed to completely dissolve 3.20 g of aluminum in this reaction?
b. What mass of AlCl3 would be produced by complete reaction of 3.20 g of aluminum?