Given that 24.0mL of 0.170 M sodium iodide reacts with 0.209M mercury(II) nitrate solution according to the unbalanced equation:
Hg(NO3)2 + NaI gives HgI2 + NaNO3
a) what volume of Hg(NO3)2 is required for complete precipitation?
b) what is the mass of HgI2 precipitate?