An unknown metal M was converted to the sulfate,M2(SO4)3. A solution of this metalsulfate was treated with excess barium chloride solution to give abarium sulfate precipitate.
M2(SO4)3 (aq) + 3 BaCl2(aq) --> 2 MCl3 (aq) + 3 BaSO4 (s)
If 1.200 grams of the metal, M results in the formation of 6.026grams of the barium sulfate product, what is the atomic weight of the unknown metal, M? What is the metal?