Consider the decomposition of liquid benzene, C6H6(l), to gaseous acetylene, C2H2(g): C6H6(l) -> 3 C2H2 (g) Change in Enthalpy = +630 kJ (a) What is the enthalpy change for the reverse reaction? (b) What is Change in Enthalpy for the formation of 1 mol of acetylene? (c) Which is more likely to be thermodynamically favored, the forward reaction of the reverse reaction? (d) If C6H6(g) were consumed instead of C6H6(l), would you expect the magnitude of Change in Enthalpy to increase,decrease, or stay the same? Explain. The following is my attempt to answer the problems: (a) -630 kJ (b) -630 kJ/ 3= -210 kJ (c) The reverse reaction? (d) C6H6(g) 82.9 Change in Hf kj/mol C6H6(g) 49.0 Change in Hf kj/mol The magnitude would increase?