When SbCl3(g) (409.0 grams) and 127.1 grams of Cl2(g) in a 120.0 L reaction vessel at 705.0 °C are allowed to come to equilibrium the mixture contains 1.302 mol of SbCl5(g). What is the equilibrium concentration (mol/L) of Cl2(g)? SbCl3(g)+Cl2(g) = SbCl5(g)