A particle moves in the xy plane with constant acceleration. At t = 0 the particle is at 1 = (4.4 m) + (3.3 m), with velocity 1. At t = 3 s, the particle has moved to 2 = (11 m) - (1.9 m)and its velocity has changed to 2 = (4.5 m/s) - (5.8 m/s).
(a) Find V1.
(b) What is the acceleration of the particle?
(c) What is the velocity of the particle as a function of time?
(d) What is the position vector of the particle as a function of time?