Problems:
Vector Calculus: Three Dimensional Space
(1) Consider the curve a→(t) = tiˆ+ t2jˆ+ t3kˆfor -1<t<1 and denote by I its path.
Compute the line integral over r of the vector field
F→ = y2i+2xyj.
(2) Consider the following four curves:
a→A(t) = sin tiˆ+ cos44tjˆ+ sin5t kˆ - ∏/2 < t < ∏/2
a→B (t) = (t+1)iˆ+ (t+1)2jˆ+(t+1)3kˆ -1 < t < 1
a→C (t) = t4iˆ - t12jˆ- t2kˆ -1< t < 1
a→D (t) = (4/1+t - 3) (iˆ + kˆ) + 1/1+t(1-t) jˆ 0 < t < 1.
Denote by τA,τB,τC and τD the corresponding paths. The integrals of the field F→ defined above over τA,τB,τC and τD give the following values, listed in ascending order:
-2, 0, 2, 32.
Associate to every curve the value of the corresponding line integral. Justify your answer.
Hint 1 : Use the result obtained in the first exercise.
Hint 2 : You do not need to compute any integral.
(3) Compute the double integral of the field ƒ= x+y/x over the region
R= {xiˆ+ yjˆ∈ ℜ2, 0 < x < 2,0 < 1/2 (y/x +1) < 1}.
Hint; The definition of the domain should suggest you a change of variables mapping R to a rectangle.
(4) Consider the following subsets of ℜ3:
T = { r→∈ℜ3, x2 + 2y2 + 3z = 1},
U = { r→∈ℜ3, x2 + 2y2 + 3z2 < 1},
V = { r→∈ℜ3, x2 + 2y2 + 3z2 = 1}
W = { r→∈ℜ3, x2 + 2y2 + 3z2 < 1, z = 0}
X = { r→∈ℜ3, x2 + 2y2 + 3z2 = 1, y = 0}
Y = { r→∈ℜ3, x2 + 2y2 + 3z = 1, y = 0}
Z = { r→∈ℜ3, x2 + 2y2 + 3z2 > 1}
Which of these are:
(i) the path of a curve,
(ii) the path of a loop,
(iii) a two-dimensional (fiat) region,
(iv) a graph surface,
(v) the boundary of a domain,
(vi) the level set of a scalar field defined on R3,
(vii) an oriented surface,
(viii) a domain?
In this exercise you do not need to justify your answer.
MILL; Note that a given set may belong to more than one class.