Compute all parts of given problem:
Problem: Two friends enter the Boston marathon. The first friend runs at a constant speed of 0.500 m/s. The second friend holds a speed of 1.00 m/s.
Part A: How far ahead is the second friend after 2.00 hours?
Part B: If the second friend promises to stop after 2 hours and wait for his slower friend to catch up, how many hours would he be waiting once he stops?
Please help for the above problem, completely confused!! Show each steps if possible, Thanks.