Two electrons in a vacuum exert force of f 411e-08 n on, Physics

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Two electrons in a vacuum exert force of f 411e-08 n on

Solve the all parts of given question:

Question: Two electrons in a vacuum exert force of F = 4.11E^-08 N on each other. They are then moved such that they are separated by x = 9.4 times their original distance.

Part A: What is the force that the electrons experience at the new distance, Fn, in Newton's?

Part B: How far apart were the electrons originally in meters?

Please show your work and steps, so I can understand process. Thank you!

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Physics: Two electrons in a vacuum exert force of f 411e-08 n on

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