Problems:
Question:
DSS Inc. is an electronics company with production facilities located in Atlanta, Boston, and Chicago. Components produced at these facilities may be shipped to the firm's regional warehouses that are located in Edison and Fargo. From the warehouses the firm supplies retail outlets located in Houston, Indianapolis, and Jacksonville.
The capacity of each production facility is presented below:
Atlanta
|
Boston
|
Chicago
|
800
|
500
|
700
|
The firm must meet the demands specified below for each retail outlet:
Houston
|
Indianapolis
|
Jacksonville
|
900
|
600
|
500
|
The transportation cost per unit from each facility to each warehouse is specified below:
|
Atlanta
|
Boston
|
Chicago
|
Edison
|
6
|
1
|
3
|
Fargo
|
4
|
8
|
1
|
The transportation cost per unit from each warehouse to each retail outlet is specified below:
|
Houston
|
Indianapolis
|
Jacksonville
|
Edison
|
8
|
3
|
4
|
Fargo
|
2
|
3
|
8
|
The firm has to determine an optimal transshipment plan that minimizes total transportation cost while meeting the demands in each retail outlet and not exceeding the capacity at each production facility.
(a) Formulate the transshipment problem as a Linear-programming model and determine the optimal transshipment plan.
(b) In the analysis so far we have ignored the cost of operating each warehouse. If a warehouse is operated, a fixed cost must be incurred. If a warehouse is not operated, the fixed cost can be avoided but no shipment can occur through that warehouse. ). The fixed costs for warehouse operation are given below:
|
Cost
|
Edison
|
$10,000
|
Fargo
|
$5,000
|
Determine the optimal plan that minimizes the total cost (total cost is defined as the sum of the cost of transportation and the cost warehouse operation).
My partial Answer:
XAE , XAF , XBE , XBF , XCE , XCF , XEH , XFH , XEI , XFI , XEJ , XFJ
Capacity Constrains:
XAE + XAF ≤ 800
XBE + XBF ≤ 500
XCE + XCF ≤ 700
Demand Constrains:
XEH + XFH ≤ 900
XEI + XFI ≤ 600
XEJ + XFJ ≤ 500
XAE + XBE + XCE = XEH + XEI + XEJ
XAF + XBF + XCF = XFH + XFI + XFJ
Objective Function:
Minimize the cost = 6XAE + 4XAF + XBE + 8XBF + 3XCE + XCF + 8XEH + 2XFH + 3XEI + 3XFI + 4XEJ + 8XFJ
b) Three options:
Keep both warehouses open: add operating cost of $15000
Close Fargo: add operating cost of $10000
Close Edison: add operating cost of $5000