Te total admittance for the following circuit is hint yt


(1) Determine the resonance frequency of the following circuit to the nearest integer value.

R = 100 ohm

C = 4UF

L = 80 mH

(a) 563 HZ

(b) 1125 HZ

(c) 281 HZ

(d) 1000 HZ

 

(2) For the parallel Ac circuit shown below, find the current Is. Note that Vin Ac is mpislabelled, it should be 10 V, NOT 10 sin(wt)

Data:

Vin AC= 10sin(wt)

R = 100 ohm

Xc = 100 ohm

XL = 100 ohm

(a) 0.1 + j0.1A

(b) 0.1 - j 0.1 A

(c) 0.1 A

(d) j0.2 A

 

(3) The total admittance for the following circuit is

Hint: YT = G + j[Bc - BL] Siemens; G = 1/R Siemens; Bc = wC Siemens and BL = 1/[wL] Siemens

Data:

Vin AC = 10 sin 1250t

R = 100

C = 4UF

L = 80 mH

(a) 0.01 - j0.05 Siemens

(b) 0.01 + 0.005 Siemens

(c) 0.01 - j0.05 Siemens

(d) 0.001 - 0.005 siemens

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Electrical Engineering: Te total admittance for the following circuit is hint yt
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