The resistivity of pure copper is 1.56 micro-ohm -cm. An alloy of copper contains 1 atomic percent nickel has a resistivity of 2.81 micro-ohm-cm. An alloy of copper containing 3- atomic percent silver has a resistivity of 1.98 micro-ohm -cm. What is the resistivity of an alloy of copper containing 2 atomic percent nickel and 2 atomic percent silver?
Ans:
ρcu = 1.56
ρ(cu + Ni) = 2.81
ρ1, raise in resistivity for one atomic percent-added impurity as Nickel
ρ1( Nickel ) = 1.25 = 2.81 -1.56 = 1.25
ρ1( Silver ) = (1.98 - 1.56)/3 = 0.14
ρalloy = 1.56 + 2 ×1.25 + 2 × 0.14 = 4.34 µ? - cm.