The position vector of a particle of mass 180 kg as a, Physics

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The position vector of a particle of mass 180 kg as a

The position vector of a particle of mass 1.80 kg as a function of time is given by r = (6.00i + 4.60t j ), where r is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time. Answer should be in: ( k vector) kg · m2/s

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