The other half of the satellite is and tip temperature for


Consider the spherical satellite of Problem 12.130. Instead of the entire satellite being coated with a material that is spectrally selective, half of the satellite is covered with a diffuse gray coating character(c) Use your computer code to calculate the heat rateized by a1 = 0.6. The other half of the satellite is and tip temperature for GS = 0 and an extremely large value of the thermal conductivity. Compare coated with a diffuse gray material with a2 = 0.3.

Your results to those obtained from a hand calculation that assumes the radiator to be at a uniform temperature Tb. What other approach might you use to validate your code?

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Mechanical Engineering: The other half of the satellite is and tip temperature for
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