Problem- Consider the following electrochemical cell at 298 K. One compartment contains a 1.00-M solution of silver nitrate. The other compartment contains a saturated solution of silver iodide. Both electrodes are silver and the measured potential is 0.476 V. From this information, determine the molar solubility of silver iodide at 298 K.
The answer is 9.11 x 10?9
If possible just a to the point details about how you got the answer?