The length of a rectangle is 8 ft more than the width

Question

1. Factor completely using the trial-and-error method.

4x² –6x –28

2. Factor completely using the trial-and-error method.

7x² + 7x – 14

3. Solve by factoring.

(x – 5)(x + 9) = 0

4. Find the zeros of the function.

f(x) = 6x² – 30x – 36

5. The length of a rectangle is 8 ft more than the width.  If the area of the rectangle is 65 ft2, find the dimensions of the rectangle.

6. Factor completely, if possible.

8x² + 15x + 2