The growth of S. cerevisiae on glucose under anaerobic conditions can be described by the following overall reaction:
C6H12O6 - ?N NH3 ?? 0.59 CH1.74N0.2O0.45 (biomass) + 0.43 C3H8O3 + 1.54 CO2
a). Determine the biomass yield factor: YFX/S. (biomass/sugar)
b). Determine the product yield factor: YFEtOH/S, YFCO (Ethanol/sugar)
c). Determine the coefficient ?N,
Major delimma is determining the molecular weight of the biomass, as it has partial atoms, (C)(H1.74)(N0.2)(O.25)
The biomass consist of
Carbon - 1
Hydrogen - 1.74
Nitrogen - .2
Oxygen .25
This seems to be what's throwing me off.