The given equation 3 C2H5OH + 4 KMnO4 --> 3 CH3COOH + 4 MnO2 + 4 MnO2 + H2O describes the oxidation of ethanol (C2H5OH) to acetic acid (CH3COOH) by potassium permanganate (KMn04): now calculate what is the theoretical yield of CH3COOH if 5.00 g of C2H5OH and 10.00 g of KMnO4 react also determine the actual yield If the percent yield of the reaction in B was 91%,?