The gaseous hydrocarbon butane c4h10 burns according to the
The gaseous hydrocarbon butane, C4H10, burns according to the following equation:
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
How many grams of CO2 are produced from the complete reaction of 55.6 g of C4H10? Express your answer with the appropriate units.
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the gaseous hydrocarbon butane c4h10 burns according to the following equation2c4h10g13o2grarr8co2g10h2oghow many grams
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