The fourier transforms of odd and even functions are very


The Fourier transforms of odd and even functions are very important. The reason is that they are computationally simpler than the Fourier transform. Let x(t) = e-ItI and y(t) = e-tu(t) - etu(-t).
a. Plot x(t) and y(t), and determine whether they are odd or even.
b. Show that the Fourier transform of x(t) is found from x(Ω ) = ∫ (xt )cos (Ωt )dt , which is a real function of Ω , thus its computational importance. Show that X( Ω) is also even as a function of (Ω ).
c. Find x(Ω ) from the above equation (called the cosine transform).
d. Show that the Fourier transform of y(t) is found from y( Ω) = -j ∫ (yt ) sin(Ωt )dt , which is the imaginary function of (Ω ), thus its computational importance. Show that Y( Ω) is also odd as a function of (Ω ).
e. Find Y(Ω ) from the equation above (called the sine transform). Verify that your results are correct by finding the Fourier transform of z(t) = x(t) + y(t) directly and using the above results.
f. What advantages do you see to the sine and cosine transforms> How would you use cosine and the sine transforms to compute the Fourier transform of any signal, not necessarily even or odd, explain.

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Electrical Engineering: The fourier transforms of odd and even functions are very
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