The equilibrium constant of a reaction is 104e02 at 362 k


The equilibrium constant of a reaction is 1.04e+02 at 362 K and 2.39e+03 at 465 K. Determine the following for this reaction:
Ho= kJ/mol
So= J/mol-K
What is the value of the equilibrium constant at 414 K?
K=

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Chemistry: The equilibrium constant of a reaction is 104e02 at 362 k
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