The combustion of b2h6 occurs according to the following


The combustion of B2H6 occurs according to the following equation. Using the enthalpies of formation, calculate the energy (kJ) released when 4.00 g of B2H6 reacts.

(Atomic weights: B = 10.81, O = 16.00, H = 1.008).

B2H6(g) + 3 O2(g) B2O3(s) + 3 H2O(g)

Ho B2H6(g) = -57.4 kJ/mole

Ho B2O3(s) = -1273 kJ/mole

Ho H2O(g) = -241.8 kJ/mol

Request for Solution File

Ask an Expert for Answer!!
Chemistry: The combustion of b2h6 occurs according to the following
Reference No:- TGS0568747

Expected delivery within 24 Hours