Te wheel has mass m radius r and moment of inertia ig


The wheel has mass m, radius R and moment of inertia IG = mR2/2. The wheel is initially at rest, and it is subjected to a pair of forces with equal magnitude F and opposite directions as shown. When the wheel rolls without slipping, the coefficient of friction between the wheel and the floor is μs = .5. When the wheel rolls and slips, the coefficient of friction between the wheel and the floor is μk = .3. Find the acceleration of the center of the wheel if

1697_Figure.png

(a) F = mg/2,

(b) F = mg.

Solution Preview :

Prepared by a verified Expert
Mechanical Engineering: Te wheel has mass m radius r and moment of inertia ig
Reference No:- TGS01507506

Now Priced at $15 (50% Discount)

Recommended (94%)

Rated (4.6/5)