Suppose that A and B are n x n matrices such that A = SBS-1 (where S is an invertible matrix), so A and B are similar matrices.
(a) Show: if v is an eigenvector of B with eigenvalue μ, then Sv is an eigenvector for A.
(Remember that only nonzero vectors can be eigenvectors.)
What is the corresponding eigenvalue?
(b) Suppose that w is an eigenvector of A with eigenvalue β. Find an eigenvector for B which has the same eigenvalue β.