Show transcribed image text The surface area of a right-circular cone of radius r and height h is S = pir root r^2 + h^2, and its volume is V = 1/3 pir^2h. (a) Determine h and r for the cone with given surface area S = 6 and maximal volume V. h= r= (b) What is the ratio h/r for a cone with given volume V=6 and minimal surface area S? h/r=