Question 1
Reduce the following level sheet showing all checks. Compute the adjusted reduced levels for all points.
|
BS
|
INT
|
FS
|
Rise
|
Fall
|
RL
|
Remarks
|
|
2.567
|
|
|
|
|
|
PSM 162 (RL = 37.855)
|
|
1.984
|
|
3.984
|
|
|
|
TBM A
|
|
0.355
|
|
0.768
|
|
|
|
TBM B
|
|
3.031
|
|
3.804
|
|
|
|
TBM C
|
|
0.783
|
|
2.547
|
|
|
|
TBM D
|
|
|
2.541
|
|
|
|
|
Natural Surface
|
|
|
2.895
|
|
|
|
|
Natural Surface
|
|
3.651
|
|
0.784
|
|
|
|
TBM E
|
|
3.981
|
|
2.189
|
|
|
|
TBM F
|
|
|
|
2.283
|
|
|
|
PSM 162 (RL = 37.855)
|
|
|
|
|
|
|
|
|
Question 2
Calculate the index error for an automatic level based on the tabulated measurements below
|
Two Peg Test
|
|
At
|
To
|
Distance
|
Reading
|
|
Mid.Pt
|
501
|
30
|
2.136
|
|
Mid.Pt
|
502
|
30
|
1.826
|
|
502
|
502
|
1
|
1.625
|
|
502
|
501
|
60
|
1.959
|
Question 3
|
Line
|
Bearing
|
Distance
|
?E
|
?N
|
E
|
N
|
|
|
Deg
|
Min
|
Sec
|
metres
|
|
|
|
|
|
A
|
|
|
|
|
|
|
1000.000
|
2000.000
|
|
A-B
|
57
|
56
|
40
|
111.505
|
|
|
|
|
|
B-C
|
135
|
20
|
30
|
84.256
|
|
|
|
|
|
C-D
|
179
|
55
|
50
|
47.269
|
|
|
|
|
|
D-E
|
255
|
15
|
10
|
78.988
|
|
|
|
|
|
E-A
|
311
|
21
|
20
|
103.11
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
From the closed traverse information above, compute coordinates of Stations B, C, D and E.
Question 4
Convert
(a) 2.5764o to Degrees Minutes Seconds
(b) 204o 39'43" to Degrees Decimals
Question 5
What is the height difference between A and B given the following measurements:
- the height of the instrument (hi) at A is 1.272m and the height of the target at B (ht) is 1.333
- zenith angle (z) and slope distance (s) is 82o 52'36" and 127.025m respectively.
Question 6
The reduced level of 901 is to be determined by trig heighting from instrument station 1. Given the height difference from 1 to 728 is -0.421m and 1 to 901 is +1.527m. If the RL of 728 is 26.505m calculate the RL of 901.
Question 7
Given the bearing and direction of one line calculate the bearings of the remaining lines.
Question 8
|
At Station
|
To
|
Face Left
|
Face Right
|
|
PM 01
|
PM02
|
244o55' 30"
|
64o55'28"
|
|
|
PM 03
|
45o00'10"
|
225o00'16"
|
Calculate the mean of the measured angle from the following observed bearings
Question 9
Distances were measured on all sides of the triangle ABC as shown below. Compute the values of internal angles in degrees minutes and seconds.
