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Rate of heat loss by natural convection


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Q: A hot plate with an insulated back is considered. The rate of heat loss by natural convection is to be determined.

(Ts+T∞)/2=(130+75)/2=102.5 °F
k=0.01535 Btu/h./ft. °F
ν =0.1823*10^-3 ft2/s
Pr=0.7256

β=1/Tf= 1/(102.5+460)R  = ).001778R^-1

1900_plate.JPG

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Chemistry: Rate of heat loss by natural convection
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