Q. The armature of 6 -pole dc generator has a wave winding containing 664 conductors. Calculate the generator emf when flux per pole is 0.06 weber and the speed is 250 rpm. At what speed must the armature be driven to generator an emf of 250 V. If the flux per pole is reduced to 0.058 weber.
  Sol.  Given P = 6; A = 2 (as wave wound); Z = 664    Φ = 0.06,       N = 250 rpm
 
           Thus    Eg = PΦZN/60A = 6/2 × 0.06 × 664 × 250/60 = 498V
 
           Now , given Eg = 250 V; Φ = o.o58 weber
 
            Then            N = ?
 
            Thus              Eg1/Eg2 = Φ1/ Φ2 × N1/N2
 
             Or               498/250 = 0.06/0.058 × 250/N2
 
              Or           N2 = 130 rpm