q the input to the differentiator circuit is a

Question

Q. The input to the differentiator circuit is a sinusoidal voltage of peak value 5mv and frequency 1kHZ. find out the output if R=100K and C=10^-6F

Solution.

The equation of the input voltage is

V₁ = 5*sin2*3.14*1000*t = 5 sin 200 0*3.14*t mv

             = CR = (10^-6)*10^5 = 0.1

V₀ = .1*(d(5sin 2000*3.14*t)

= (.5*2000*3.14)cos 2000*3.14*t

= 1000*3.14cos2000*3.14t mv

Hence output is a cosinusoidal voltage of ferquency 1 kHZ and peak value 1000 *3.14nV.