Q. For a transistor, when vGS = -2.0 V, find VDSsat if Vp= -4.0 V for an n-channel depletion mode MOSFET.
Solution:
Vp= -(VDSsat + vSG)
but vSG = -vGS = -(-2.0) V
Substituting this in the above equation;
-4.0 V = -(VDSsat + 2.0 V)
ie VDSsat = 2.0 V
This is the value of vDS where the pinch-off will occur for the given gate-to-source voltage.