Problem based on limiting reactants
Question: When 0.629 g of Na3PO4*12H2O (molar mass = 380.12g/mol) and 0.527g of BaCl2*2H2O (molar mass = 244.30g/mol) are mixed with water forming 500ml of solution, how many grams of Ba3(PO4)2 (molar mass = 601.96g/mol) precipitates?
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When 0.629 g of Na3PO4*12H2O (molar mass = 380.12g/mol) and 0.527g of BaCl2*2H2O (molar mass = 244.30g/mol) are mixed with water forming 500ml of solution, how many grams of Ba3(PO4)2 (molar mass = 601.96g/mol) precipitates?
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