Problem- When 50.00mL of 1.000 x 10^-1 M Lead (II) nitrate solution are combined with 50.00mL of 1.000 x 10^-1 M sodium iodide solution, a precipitate is formed. 1.021g of dry solid was obtained.
Pb(NO3)2 (aq) + 2NaI (aq) -> PbI2 (s) + 2Na(NO3) (aq)
Which compound is the limiting reagent?
Based on the limiting reagent, calculate the number of moles of product that should be formed.
Calculate theoretical yield of the product
Calculate percent yield
I want you to clarify the chemistry in this above problem.